x^2-(2+3i)(x-1+3i)=0

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Solution for x^2-(2+3i)(x-1+3i)=0 equation: 


Simplifying
x2 + -1(2 + 3i)(x + -1 + 3i) = 0

Reorder the terms:
x2 + -1(2 + 3i)(-1 + 3i + x) = 0

Multiply (2 + 3i) * (-1 + 3i + x)
x2 + -1(2(-1 + 3i + x) + 3i * (-1 + 3i + x)) = 0
x2 + -1((-1 * 2 + 3i * 2 + x * 2) + 3i * (-1 + 3i + x)) = 0
x2 + -1((-2 + 6i + 2x) + 3i * (-1 + 3i + x)) = 0
x2 + -1(-2 + 6i + 2x + (-1 * 3i + 3i * 3i + x * 3i)) = 0

Reorder the terms:
x2 + -1(-2 + 6i + 2x + (-3i + 3ix + 9i2)) = 0
x2 + -1(-2 + 6i + 2x + (-3i + 3ix + 9i2)) = 0

Reorder the terms:
x2 + -1(-2 + 6i + -3i + 3ix + 9i2 + 2x) = 0

Combine like terms: 6i + -3i = 3i
x2 + -1(-2 + 3i + 3ix + 9i2 + 2x) = 0
x2 + (-2 * -1 + 3i * -1 + 3ix * -1 + 9i2 * -1 + 2x * -1) = 0
x2 + (2 + -3i + -3ix + -9i2 + -2x) = 0

Reorder the terms:
2 + -3i + -3ix + -9i2 + -2x + x2 = 0

Solving
2 + -3i + -3ix + -9i2 + -2x + x2 = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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